Deduce the condition when the De-Broglie wavelength associated with an electron would be equal to that associated with a proton if a proton is 1836 times heavier than an electron.
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Debroglie wavelength associated with particle of mass (m) moving with velocity (v) is
λ = 
λ p = 
and λ e = 
Given, λ p = λ e ⇒ 
= 
⇒ m p v p = m e v e
= 
= 1836 ⇒ v e = 1836 v p
It means when velocity of electron will be 1836 times velocity of proton, then debroglie wavelength associated with electron would be equal to debroglie wavelength associated with proton.
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